Answer:
#program in Python
#read until user Enter an integer
while True:
#try block to check integer
try:
#read input from user
inp = int(input("Enter an integer: "))
#print input
print("The integer is: ",inp)
break
#if input is not integer
except ValueError:
#print message
print("Wrong: try again.")
Explanation:
In try block, read input from user.If the input is not integer the print a message in except block.Read the input until user enter an integer. When user enter an integer then print the integer and break the loop.
Output:
Enter an integer: acs
Wrong: try again.
Enter an integer: 4a
Wrong: try again.
Enter an integer: 2.2
Wrong: try again.
Enter an integer: 12
The integer is: 12
Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
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