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Vinil7 [7]
3 years ago
10

The amount of space an object takes up

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
8 0
That is called volume. there are 2 easy ways to find that. first way: multiply the length by the width by the hight. second way: using unit 1 cubes
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Zool X
Mars2501 [29]
BOOKMARK is the answer to this question
4 0
3 years ago
Fully simplify 7c - 4h - 2c - 5h​
astraxan [27]

Answer:

5c-9h

Step-by-step explanation:

1) 7c-4h-2c-5h

2) 5c-4h-5h

3) 5c-9h

4 0
2 years ago
An amusement park offers two options. Option 1 involves a $10 admission fee plus $0.50 per ride. Option 2 involves a $6 admissio
Art [367]

Answer:

16 rides

Step-by-step explanation:

Option 1 . Admission fee = $10

                Each ride = $0.50

Option 2 . Admission fee = $6

                Each ride = $0.75

Let no. of rides be x

So, cost of ride according to option 1 = 0.50x

So, total cost after having x rides according to option 1 :

= 10+0.50x  ---1

Cost of ride according to option 2 = 0.75x  

So, total cost after having x rides according to option 2 :

= 6+0.75x  --2

Now to find the beak even point i.e. having the same cost

Equate 1 and 2

10+0.50x=6+ 0.75x

10-6= 0.75x-0.50x

4= 0.25x

\frac{4}{0.25} =x

16=x

Thus for 16 rides , the two options have the same cost .

Hence the break even point is 16 rides

5 0
4 years ago
Pq is parallel to rs the length of rp is 6cm the length of pt is 18cm the length of qt is 21cm what is the length of sq
nata0808 [166]
If this is the picture the answer is 7cm 

8 0
3 years ago
Read 2 more answers
Which equation can be solved by using this system of equations? startlayout enlarged left-brace 1st row y = 3 x superscript 5 ba
Mariulka [41]

An equation which can be used to solve the given system of equations is 3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11.

<u>Given the following data:</u>

y = 3x⁵ - 5x³ + 2x² - 10x + 4

y = 4x⁴ + 6x³ - 11

<h3>What is a system of equations?</h3>

A system of equations can be defined an algebraic equation that only has two (2) variables and can be solved simultaneoulsy.

Equating the given equations, we have:

y = y

3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11

3x⁵ - 5x³ + 2x² - 10x + 4 - (4x⁴ + 6x³ - 11) = 0

3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0

3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0

3x⁵ - 4x⁴ - 11x³ + 2x² - 10x + 15 = 0

Read more on equations here: brainly.com/question/13170908

3 0
2 years ago
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