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Aleksandr-060686 [28]
3 years ago
8

5 less than twice a number

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0

Answer:

2*x - 5

Step-by-step explanation:

Twice a number = 2 multiplied by some number (call it "x").

5 less than implies to subtract 5 from that "twice a number" result.

TiliK225 [7]3 years ago
3 0

Answer:

5 less than twice a number is 9. So, twice a number is 14.

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Multiply everything by 2 then combine like terms
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3 years ago
Amy is scuba diving. She starts at – 15.5 m relative to the ocean surface. She swims
solniwko [45]

Answer:

-9.85

Step-by-step explanation:

-15.5 - 4.2 = -19.7

Negatives work like positives

19.7 / 2 = 9.85

Turn that into a negative

-9.85

3 0
2 years ago
How do i solve a triangles area​
shusha [124]

Answer:

Area = 1/2 Base x height

Step-by-step explanation:

To find the area of a triangle, multiply the base of the height and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into two triangles.

6 0
3 years ago
What is the antiderivative of 3x/((x-1)^2)
Maslowich

Answer:

\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C

Step-by-step explanation:

Given

\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx

\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx

=3\cdot \int \frac{x}{\left(x-1\right)^2}dx

\mathrm{Apply\:u-substitution:}\:u=x-1

=3\cdot \int \frac{u+1}{u^2}du

\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}

=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx

=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)

as

\int \frac{1}{u}du=\ln \left|u\right|     ∵ \mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)

\int \frac{1}{u^2}du=-\frac{1}{u}        ∵     \mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1

so

=3\left(\ln \left|u\right|-\frac{1}{u}\right)

\mathrm{Substitute\:back}\:u=x-1

=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)

\mathrm{Add\:a\:constant\:to\:the\:solution}

=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C

Therefore,

\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C

4 0
3 years ago
Maddy and Caitlin spend a certain amount of money from their money box each month to buy bracelet-making supplies.
fomenos
Solutions 

We know that <span>Function 1 shows a greater rate of change, because Maddy spends $20 each month and Caitlin spends $18. 
</span>
Maddy spends 2 dollars more. 

Therefore the correct answer is the last option.  
<span />
8 0
3 years ago
Read 2 more answers
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