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uranmaximum [27]
3 years ago
10

How do I solve 4^-3?

Mathematics
1 answer:
Lena [83]3 years ago
7 0
If it means 4 to the power of -3.it goes as follows.

___________________________

- 64 is the answer.
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Question<br> Find the missing side lengths. Leave answer in simplest<br> radical form.
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Answer:

A) y = \frac{11\sqrt{3} }{2}, x = 11

Step-by-step explanation:

We can use the 60 degree angle to help us solve this.

Remember: tan(angle) = opposite/adjacent

Using this formula, we get that

tan (60 degrees) = y / (11/2)

This is because y is the side opposite to the 60 degree angle and 11/2 is the side adjacent to the 60 degree angle.

Simplifying this expression, we get that

\sqrt{3} = y/(11/2)

Multiplying both sides by 11/2, we get

\frac{11\sqrt{3} }{2} = y

We can now use the pythagorean theorem to help us solve for x

Remember: a² + b² = c²

Since x is the hypotenuse, it is the c value. Therefore, we get:

(11/2)² + (\frac{11\sqrt{3} }{2})² = x²

Simplifying this, we get

\frac{121}{4} + \frac{121 * 3}{4} = x²

Simplifying this some more, we get

484/4 = x²

121 = x²

Taking the square root of both sides, we get that

x = 11

I hope this helps!

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3 years ago
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