Answer:
Question 1: y-11x+5 I think; Question 2: I'm not sure
Step-by-step explanation:
Hold on need you omgg disnwkxjdjcjdjxuj ex djdusijddj
Answer:
(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.
Step-by-step explanation:
Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.
Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.
Test statistic (t) = (sample mean - population mean) ÷ sd/√n
sample mean = 3.24 minutes
population mean = 3.3 minutes
sd = 0.4 minutes
n = 62
degree of freedom = n - 1 = 62 - 1 = 71
significance level = 0.08
t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2
The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654
Conclusion:
Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.
The answer is A , because when you are finding the probability of an object , you are to divide the number of sides the object has which is 4 and put a 1 over the 4 , and you get 1/4
2.74 - (-19.4) = 22.14, so the freezer is 22.14°c colder. I hope that helps!
