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3 years ago

What is the rate and unit rate of 40 meters in 16 seconds

Mathematics

1 answer:

weqwewe [10]3 years ago

4 0

The unit rates are 40/16 = 2.5 meters per seconds and 16/40 = 0.4 seconds per minute

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Alebgra!!

Vikentia [17]

Answer:

I think it's 18

Step-by-step explanation:

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it's been awhile I believe this is it

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2 years ago

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Please answer this in steps....

SOVA2 [1]

<h2>Answer:</h2><h2>The answer is 3.14..</h2><h2>For finding it you have to divide the given numbers.</h2>

This is also a value of π (pi)

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3 years ago

NEED HELP I need to fill in the highlighted parts

Gemiola [76]

The statements and reasons why the given statements are true are presented in the following two column proofs;

Question 1

Given: 9·(x + 6) - 41 = 75

$Prove \ x = \dfrac{62}{9}$

Statement ${}$ Reason

S1. 9·(x + 6) - 41 = 75 ${}$ R1. Given

S2. 9·(x + 6) = 116 ${}$ R2. Addition property

S3. 9·x + 54 = 116 ${}$ R3. Distributive property

S4. 9·x = 62 ${}$ R4. Subtraction property

S5. $x = \dfrac{62}{9}$ ${}$ R5. Division property of equality

Question 2.

Statement ${}$ Reason

S1. m∠A + m∠B = m∠D ${}$ R1. Given

S2. ∠C and ∠D form a Linear Pair ${}$ R2. Definition of linear pair

S3. ∠C and ∠D are supplementary ${}$ R3. Linear pair ∠s are supplementary

S4. ∠C + ∠D = 180° ${}$ R4. Definition of supplementary

S5. m∠C + m∠A + m∠B = 180° ${}$ R5. Substitution property

Question 3.

Statement ${}$ Reason

S1. ∠BDA ≅ ∠A ${}$ R1. Given

S2. ∠BDA ≅ ∠CDE ${}$ R2. Vertical angle theorem

S3. ∠CDE ≅ ∠A ${}$ R3. Transitive property of congruency

S4. m∠CDE = m∠A ${}$ R4. Definition of congruency

S5. (13·x + 20)° = (14·x + 15)° ${}$ R5. Substitution Property of Equality

S6. 14·x° = 13·x + 5° ${}$ R6. Subtraction property

S7. x = 5 ${}$ R7. Subtraction property

Learn more here:

brainly.com/question/11331230

6 0

3 years ago

Help!! I'll give points if anybody can answer these for me!

galina1969 [7]

Transformation involves changing the position of a shape.

The transformation from $\triangle ABC$ to $\triangle A'B'C'$ is 90 degrees clockwise rotation

Using the coordinates of A and A', we have:

$A= (-6,3)$

$A'= (3,6)$

Notice that the x-coordinate is negated and then swapped with the y-coordinate.

i.e.

$(x,y) \to (y,-x)$

The transformation of a point from (x,y) to (y,-x) is a 90 degrees clockwise rotation.

Hence, the transformation from $\triangle ABC$ to $\triangle A'B'C'$ is 90 degrees clockwise rotation