<span>All real numbers that are greater than –6 but less than 6 is written as -6 < x < 6</span>
Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
152 
Step-by-step explanation:
We know that the total surface area of a cuboid is the sum of the surface area of all six of its faces.
We also know that each opposing side has the same surface area. Thus the total surface area is equal to:
()
<span>Least Common Denominator (LCD) is the least number which all the denominators can divide without remainder. The given denominators are 2, 16 and 8. The least number 2, 16 and 8 will divide without remainder is 16. Therefore, to express the fractions 1/2, 3/12, and 7/8 with an LCD, we multiply both the numerator and the denominator of each of the fractions with a common factor that makes the denominator to be 16. Therefore, 1/2, 3/16 and 7/8 expressed with an LCD are (1 x 8) / (2 x 8), 3/16, (7 x 2) / (8 x 2) = 8/16, 3/16, and 14/16.</span>
