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zmey [24]
3 years ago
14

Find the 25th term of an arithmetic sequence whose first term is 12 and whose common difference is ‒6.

Mathematics
1 answer:
blondinia [14]3 years ago
8 0
C -132 is the answer
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Find the number which when divided by 4 and increased by 12 is the same as when it is divided by 3 and decreased by 5
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Step-by-step explanation:

Let's make the number we're finding to be a. So, it says that it will be divided by 4 and then added by 12 if we want this in algebraic expression it will be \frac{a}{4} +12\\. It's also telling us that that expression is the same thing as our number divided by 3 and subtracted by 5. If we want an expression out of it it well be \frac{a}{3} -5\\. Since they are the same, we have the equation below.

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All we have to do now is to find a.

\frac{a}{4} +12 = \frac{a}{3} -5 \\ \frac{a +48}{4} = \frac{a -15}{3} \\ (3)(a +48) = (a - 15)(4) \\ 3a +144 = 4a -60 \\ (60 -3a) + 3a +144 = 4a -60 +(60 -3a) \\ a = 204

<h3>Answer:</h3>

Our number must be 204. I think

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The ratio of boys to girls at a local sports club is 3 to 1 if there are 45 girls, how many boys are there
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What is the solution to 3!
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