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4 years ago

Which set of points is collinear? Please answer ASAP

Mathematics

1 answer:

Mars2501 [29]4 years ago

6 0

Answer:

third one

Step-by-step explanation:

the slope is one that's why

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TO ANYONE WHO WILL HELP ME..

NikAS [45]

Answer:

there isn't a math question

Step-by-step explanation:

4 0

3 years ago

PLEASE HELP ME ANSWER THIS<br> What is cos 60?

Anna71 [15]

Answer:

The angle with measure 60° is one of those angles that has a well-known cosine value: cos(60°) its C= 1/2.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

While making oatmeal cookies, Angela needs to add 1/2 cup of milk to her dough. However, she has only a 1/4-cup measuring cup. H

drek231 [11]

Answer:

Step-by-step explanation:

5 0

3 years ago

How to get the answers?

beks73 [17]

By inclusion/exclusion,

$n(P' \cup Q) = n(P') + n(Q) - n(P' \cap Q)$

We have

$n(\xi) = n(P) + n(P') \implies n(P') = 28 - n(P)$

so that

$n(P' \cup Q) = (28 - n(P)) + n(Q) - 2n(P) = 28 - 3n(P) + n(Q)$

Now,

$n(\xi) = 28 \implies n(P \cup Q) = 28 - 7 = 21$

and by inclusion/exclusion,

$n(P \cup Q) = n(P) + n(Q) - n(P \cap Q)$

Decompose $Q$ into the union of two disjoint sets:

$Q = (P \cap Q) \cup (P' \cap Q)$

Since they're disjoint,

$n(Q) = n(P\cap Q) + n(P'\cap Q) \implies n(Q) = n(P\cap Q) + 2n(P)$

$\implies n(P \cup Q) = n(P) + (n(P\cap Q) + 2n(P)) - n(P \cap Q)$

$\implies 21 = 3n(P)$

$\implies n(P) = 7$

From the Venn diagram, we see there are 3 elements unique to $P$ - by the way, this is the set $P \cap Q'$ - so $n(P\cap Q) = 7-3 = 4$ , and it follows that

$n(Q) = n(P\cap Q) + 2n(P) = 4 + 2\times7 = 18$

Finally, we get for (a)

$n(P' \cup Q) = 28 - 3n(P) + n(Q) = 28 - 3\times7 + 18 = \boxed{25}$

For (b), we have by inclusion/exclusion that

$n(P \cup Q') = n(P) + n(Q) - n(P \cap Q') = 7 + 18 - 3 = \boxed{22}$

5 0

2 years ago

Matthew drove 74 miles in 2 hours. On average,how fast did he drive in hours per mile?

Lynna [10]

Answer:

37 mph

Step-by-step explanation:

Step 1:

74 ÷ 2

Answer:

Hope This Helps :)

4 0

4 years ago