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Leya [2.2K]
4 years ago
15

What is the slope of the line through the points (5, -3) and (2, -1)?

Mathematics
1 answer:
Luden [163]4 years ago
5 0
HI i THINK THE ANSWER IS <span>"two plus two equals five"</span>
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Tom grew eight tomato plants with four seeds packets. How many seed packets does Tom need to have a total of 16 tomato plants?
Dmitriy789 [7]

Answer:

8 seed packets

Step-by-step explanation:

you just need to have half the amount of seed packets of the number of tomato plants grown

8 0
3 years ago
Jim had one hour to get to the
k0ka [10]
Jim has 27.5 minutes left to get to the airport.
7 0
3 years ago
The diagram above, not drawn to scale,shows a triangle, ABC, with area 28units². Show workings.
Valentin [98]

A. (0,-6)
plug in the area to the area formula for a triangle (A=1/2bh). so 28=1/2b(4) [since the height is 4]. divide by 4 (7=1/2b). multiply by 2/divide by 1/2 (14=b). the base equals 14 units long.
B. y=2/3x+4
find the slope of the line (2/3)
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4 0
3 years ago
Please help me and show your working out thank youu
slava [35]

Answer:

Step-by-step explanation:

mm = 1357

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5 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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