128 pencils divided by 6 pencils that can be put in a box; 128÷6=21 with a remainder of 3
Martin needs 3 more pencils for the last box, beacuse he has 3 leftovers and 6 can go into the box. 6-3=3
<span>(15/4)*z + 12?... I tried working with different ways on the calculator to get the answer and that might be it.</span>
What is the X in the problem
