4y – 5х = 3(4х – 2y + 1) in standard form
1 answer:
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Answer:
T'
Step-by-step explanation:
See the diagram attached.
This is a unit circle having a radius (r) = 1 unit.
So, the length of the circumference of the circle will be 2πr = 2π units.
Now, the point on the circle at a distance of x along the arc from P is T.
Therefore, the point on the circle at a distance of 2π - x along the arc from P will be T' , where, T' is the image of point T, when reflected over the x-axis. (Answer)