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Nadusha1986 [10]
2 years ago
15

4y – 5х = 3(4х – 2y + 1) in standard form​

Mathematics
1 answer:
posledela2 years ago
3 0

Answer:

The answer is -17x + 10y = 3

Step-by-step explanation:

Hope this helps

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Is 8 a factor of 54t - 63 ?
shepuryov [24]

Answer:

yes it is i got a hundered on my test

5 0
3 years ago
Two companies rent boats by the hour. The total cost, in dollars, c, depends on the number of hours, h.
Maurinko [17]

Answer:

A(35)

B(35_20=15

Step-by-step explanation:

same as all above

3 0
2 years ago
Two patrol boats leave Cape May at the same time, the same speed, but on different bearings. One has bearing 41°45
VMariaS [17]

Based on the information given, the computation shows that the distance between them is 2.47 miles.

<h3>Solving the distance.</h3>

Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.

The other has bearing 59°13'. This will be:

= 59° + (13/60) = 59° + 0.22 = 59.22°.

The difference of the angles will be:

= 59.22° - 41.75°

= 17.47°

Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:

c² = a² + b² - 2ab cos 17.47°

c² = 20² + 20² - (2 × 20 × 20 × 0.19)

c² = 6.07459

c = 2.47

Learn more about distance on:

brainly.com/question/2854969

8 0
2 years ago
Use CALCULUS to find coordinates of the turning point on C.
antiseptic1488 [7]
Oi 

Just calculating the differential. Step by step:

y=12 \sqrt{x} -x \frac{3}{2}-10 \\  \\ y=12x^{ \frac{1}{2} } -x \frac{3}{2}-10 \ \ \ \boxed{transform \  \sqrt{x} =x^{ \frac{1}{2} }}  \\  \\  Differentiating \\  \\ y'=12. \frac{1}{2}.x^{ \frac{1}{2}-1 } -1.x^{1-1}. \frac{3}{2}-0 \\  \\  y'=6.x^{ -\frac{1}{2} } -x^{0}. \frac{3}{2} \\  \\  y'=6. \frac{1}{x^{ \frac{1}{2} }}  -1. \frac{3}{2}  \\  \\  \boxed{y'=\frac{6}{ \sqrt{x} }  -\frac{3}{2}}

If you want to know where the tangent has no slope:

\frac{6}{ \sqrt{x} } - \frac{3}{2} =0 \\  \\  \frac{6}{ \sqrt{x} } = \frac{3}{2}  \\  \\ 3 \sqrt{x} =12 \\  \\  \sqrt{x} = \frac{12}{3}  \\  \\  \sqrt{x} =4 \\  \\   (\sqrt{x})^2 =4^2 \\  \\ x=16
3 0
3 years ago
1.name two acute angles in the figure
kirill115 [55]

Answer:

There isn't a figure. But Acute angles are less than 90 degrees(they're small than an L). Remember it by saying "cute" things are small so acute

Step-by-step explanation:

6 0
3 years ago
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