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Zarrin [17]
3 years ago
6

Solve the system of linear equations.(Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.

If the system has an infinite number of solutions, set X3 = t and solve for x1 and X2 in terms of t.)
4x1 - 3X2 + 5X3 = 2
X1 + x2 - 2x3 = 3
3x1 - 4x2 + 7X3 = 9

(X1,X2,X3)=

Mathematics
1 answer:
NARA [144]3 years ago
3 0

Answer:

No solution!

Step-by-step explanation:

Kindly see the attached file for processed solution

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1 Austin earned 47 out of 50 points on his math test. Marty earned a 92% on his math test. Who earned a higher score? Marty or A
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Answer:

Austin earned a higher score

Step-by-step explanation:

47/50 (Austin's score) = 94/100 (denominator is now 100) = 94% (converted to percentage) > 92% (Marty's score)

Hope this helps!

8 0
3 years ago
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2k - 2j when j=4&k=6 replace the variable with the given amount and solve the problem​
eimsori [14]

Answer:

4

Step-by-step explanation:

first, plug in 6 for k.<em> (</em><em>i</em><em>t</em><em> </em><em>doesn't</em><em> </em><em>matter</em><em> </em><em>which</em><em> </em><em>value</em><em> </em><em>you</em><em> </em><em>plug</em><em> </em><em>in</em><em> </em><em>first</em><em>;</em><em> </em><em>you can start with j </em><em>o</em><em>r</em><em> </em><em>k</em><em>,</em><em> </em><em>but i'm just </em><em>s</em><em>t</em><em>a</em><em>r</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>with</em><em> </em><em>k</em><em> </em><em>since</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>v</em><em>a</em><em>r</em><em>i</em><em>a</em><em>b</em><em>l</em><em>e</em><em> </em><em>that</em><em> </em><em>comes</em><em> </em><em>first</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>expression</em><em>)</em>

2k - 2j => 2(6) - 2j

then plug in 4 for j.

2(6) - 2j => 2(6) - 2(4)

now your expression is 2(6) - 2(4). simplify by multiplying 2(6) and then -2(4) <em>(</em><em>again</em><em>,</em><em> </em><em>it</em><em> </em><em>doesn't</em><em> </em><em>matter</em><em> </em><em>which</em><em> </em><em>one</em><em> </em><em>you</em><em> </em><em>multiply</em><em> </em><em>first</em><em>,</em><em> </em><em>as</em><em> </em><em>long</em><em> </em><em>as</em><em> </em><em>you</em><em> </em><em>make</em><em> </em><em>sure</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>minus</em><em> </em><em>sign</em><em> </em><em>between</em><em> </em><em>2</em><em>(</em><em>6</em><em>)</em><em> </em><em>and</em><em> </em><em>2</em><em>(</em><em>4</em><em>)</em><em> </em><em>gets</em><em> </em><em>attached</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>2</em><em> </em><em>in</em><em> </em><em>2</em><em>(</em><em>4</em><em>)</em><em>.</em><em>)</em>

2(6) - 2(4) => 12 - 2(4)

12 - 2(4) => 12 - 8

subtract 8 from 12.

12 - 8 = 4

your answer is 4, therefore when j = 4 and k = 6, 2k - 2j = 4.

i hope this helps! have a nice day <3

8 0
3 years ago
A realtor uses a lock box to store the keys to a house that is for sale. The access code for the lock box consists of sixsix dig
vazorg [7]

Answer:

450,000 codes

Step-by-step explanation:

Number of digits in the access code = 6

Conditions:

  • First digit cannot be 2
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Since, there are 10 digits in total from 0 to 9 and first digit cannot be 2, there are 9 ways to fill the place of first digit.

Last digit must be odd. As there are 5 odd digits from 0 to 9, there are 5 ways to fill the last digit.

The central 4 digits can be filled by any of the 10 numbers. So, each of them can be filled in 10 ways.

According to the fundamental rule of counting, the total possible codes would be the product of all the possibilities of individual digits.

Therefore,

Number of possible codes = 9 x 10 x 10 x 10 x 10 x 5 = 450,000 codes

Hence, 450,000 different codes are possible for the lock box

8 0
4 years ago
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Jlenok [28]

50 \times 8 = 400 \\ 400 - 575 =  - 175
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8 0
3 years ago
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tatyana61 [14]
1. 45
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4 years ago
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