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andre [41]
3 years ago
9

Five houses in the neighborhood sold this month for the following prices:

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

70,000

Step-by-step explanation:

Median= 345,000

Higest selling house= 415,000

415,000-345,000= 70,000

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Rob deposits $3,500 at Town Bank,
rjkz [21]
Yeah I don’t know but have someone else
8 0
3 years ago
Is -1 and 4/5 greater than -2 and 1/8
Goryan [66]
Hey there!

The correct answer is yes.


The smaller the number with a negative sign, the larger the number actually is.
So, -1 4/5 > -2 1/8

Hope this helps! :)
6 0
3 years ago
Your math professor gives you a set of 10 problems and tells you that the final exam will consist of a random selection of 5 of
stellarik [79]

Answer:

0.083

Step-by-step explanation:

To solve the above question, we use the combination method.

C(n, r) = nCr = n!/r!(n - r)!

Probability of answering (all 5 correctly)

= Probability of answering ( 5 out of 7 correctly)/ Probability of answering (5 out of 10 problems)

Probability of answering ( 5 out of 7 correctly) = 7C5

nCr = n!/r!(n - r)!

= 7!/5! (7 - 5)!

= 7 × 6 × 5 × 4 × 3 × 2 × 1/( 5 × 4 × 3 × 2 × 1) × (2 × 1)

= 21 ways

Probability of answering (5 out of 10 problems) = 10C5

nCr = n!/r!(n - r)!

= 10!/5! (10 - 5)!

= 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/( 5 × 4 × 3 × 2 × 1) × (5 × 4 × 3 × 2 × 1)

= 252 ways

Probability of answering (all 5 correctly)

= 21/252

= 0.0833333333

Approximately = 0.083

5 0
3 years ago
A radio tower is located on a coordinate system measured in miles. The range of a signal in a particular direction is modeled by
GalinKa [24]
Given that the range of the signal is a quadratic function: (x-h)^2 = 4a (y - k) (5-4)^2 = 4a (4 - 2) 4a =1/2 therefore, (x -4)^2 = (1/2)(y – 2) The road is a line. Slope of the road is (7 -2)/(-3 -8) =-5/11 Therefore the equation of the line: 5x + 11y = 5(8) + 11(2) 5x + 11y = 62
4 0
4 years ago
Read 2 more answers
Prove that a cubic equation x 3 + ax 2 + bx+ c = 0 has 3 roots by finding the roots.
evablogger [386]

That's a pretty tall order for Brainly homework.  Let's start with the depressed cubic, which is simpler.

Solve

y^3 + 3py = 2q

We'll put coefficients on the coefficients to avoid fractions down the road.

The key idea is called a split, which let's us turn the cubic equation in to a quadratic.  We split unknown y into two pieces:

y = s + t

Substituting,

(s+t)^3 + 3p(s+t) = 2q

Expanding it out,

s^3+3 s^2 t + 3 s t^2 + t^3 + 3p(s+t) = 2q

s^3+t^3 + 3 s t(s+t) + 3p(s+t) = 2q

s^3+t^3 + 3( s t + p)(s+t) = 2q

There a few moves we could make from here. The easiest is probably to try to solve the simultaneous equations:

s^3+t^3=2q, \qquad st+p=0

which would give us a solution to the cubic.

p=-st

t = -\dfrac p s

Substituting,

s^3 - \dfrac{p^3}{s^3} = 2q

(s^3)^2 - 2 q s^3 - p^3 = 0

By the quadratic formula (note the shortcut from the even linear term):

s^3 = q \pm \sqrt{p^3 + q^2}

By the symmetry of the problem (we can interchange s and t without changing anything) when s is one solution t is the other:

s^3 = q + \sqrt{p^3+q^2}

t^3 = q - \sqrt{p^3+q^2}

We've arrived at the solution for the depressed cubic:

y = s+t = \sqrt[3]{q + \sqrt{p^3+q^2}} + \sqrt[3]{ q - \sqrt{p^3+q^2} }

This is all three roots of the equation, given by the three cube roots (at least two complex), say for the left radical.  The two cubes aren't really independent, we need their product to be -p=st.

That's the three roots of the depressed cubic; let's solve the general cubic by reducing it to the depressed cubic.

x^3 + ax^2 + bx + c=0

We want to eliminate the squared term.  If substitute x = y + k we'll get a 3ky² from the cubic term and ay² from the squared term; we want these to cancel so 3k=-a.

Substitute x = y - a/3

(y - a/3)^3 + a(y - a/3)^2 + b(y - a/3) + c = 0

y^3 - ay^2 + a^2/3 y - a^3/27 + ay^2-2a^2y/3 + a^3/9 + by - ab/3 + c =0

y^3 + (b - a^2/3) y = -(2a^3+9ab) /27

Comparing that to

y^3 + 3py = 2q

we have p = (3b - a^2) /9, q =-(a^3+9ab)/54

which we can substitute in to the depressed cubic solution and subtract a/3  to get the three roots.  I won't write that out; it's a little ugly.

8 0
4 years ago
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