Hello,
$\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\


$
x=-1.81053571 and y=<span> 5,27803957 </span>

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2 years ago

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Whats the answer to (m-n)(-3)

Likurg_2 [28]

The answer is -3m + 3n

3 0

3 years ago

(-9,7),(9,1) What is the​ point-slope form of the equation of the​ line?

(-9,7),(9,1) What is the point-slope form of the equation of the line?