2 years ago

PLEASE HELP!!!!!!!!

Mathematics

1 answer:

Nataly [62]2 years ago

6 0

Answer:

C. Y=1,200(1-0.035)x

Step-by-step explanation:

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3 years ago

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A small metal bar, whose initial temperature was 10° C, is dropped into a large container of boiling water. How long will it tak

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According to newton law of cooling

$\dfrac{d T}{dt} = k (T - T_a)$

and

$T = Ce^{kt} + T_a$

now At Ta = 100

T₀ = 10 °C

T₁ = 12° C

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now,

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$e^k = \dfrac{88}{90}$

$k = ln{\dfrac{88}{90}}$

at time equal to t

T(t) = 70

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$70 = -90(\dfrac{88}{90})^t + 100$

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t = 48.88 s

hence, after 48.88 s the temperature of the body will be 70°C

b) time taken to reach 98°C

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$98 = -90(\dfrac{88}{90})^t + 100$

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t = 390 s

hence, after 390 s the temperature of the body will be 98°C

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2 years ago