They made profit of 
by selling 190 kg of taffy in 400 g bags at rate of 
each.
<u>Solution:
</u>
Given that
To raise money, the Boy Scouts bought 190 kg of taffy for 
.
They sold the tafty in 400 g bags for 
Need to calculate the profit the made.
Cost price of 190 kg of taffy =
As 1 kg = 1000 gram,
So 190 kg of taffy = 
So cost price of 190000 gram of taffy =
Now let us calculate number of 400 grams bags which can be made from 190000 grams of taffy
Number of 400 grams bags = 
Amount generated from 1 bag of 400 gram taffy = 3.28
So amount generated from 475 bags of taffy = 
Selling price of 190000 grams of taffy = amount generated from 475 bags of taffy = 
Hence they made profit of by selling 190 kg of taffy in 400 g bags at rate of
Answer
If you would like it in numbers it would be 16.970562748
ANSWER and EXPLANATION
We want to order the functions from widest to narrowest:
To do this, we have to plot the graphs of the functions by using a table of values.
Let us find the values of the functions for values of x = -2, 0, 2
For the first function:
Hence, its table is:
For the second function:
Hence, its table is:
For the third function:
Hence, its table is:
Now, let us plot the graphs of the functions:
Therefore, from the graph, we see that the order of the functions from widest to narrowest is:
Answer: Line AC = 24 units and line BC = 12 units.
Step-by-step explanation: Please refer to the diagram attached for more details.
The right angled triangle ABC has been drawn with angle A measuring 30 degrees and line AB measuring 12√3. To calculate the other two unknown sides AC labelled b, and BC labelled a, we shall use the trigonometric ratios. However, in this scenario, we shall apply the special values of each trigonometric ratio. These are shown in the box on the top right in the picture. The proof is given in the second right angled triangle at the bottom part of the attached picture.
Assume an equilateral triangle with lengths 2 units on all sides and 60 degrees at all angles. Drawing a line perpendicular to the bottom line would divide the top angle into two equal halves (30 degrees each), and the bottom line also would be divided into two equal halves (1 unit each). So the hypotenuse will measure 2 units and the line at the base would measure 1 unit. By using the Pythagoras' theorem, we derive the third side to be √3 <u>(that is x² = 2² - 1², and then x² = 4 - 1, and then x² = 3 and finally x = √3).</u>
Therefore, in triangle ABC, using angle 30 as the reference angle, to calculate side AC;
Cos 30 = Adjacent/Hypotenuse
Cos 30 = (12√3)/b
b = (12√3)/Cos 30
Where Cos 30 is √3/2
b = (12√3)/√3/2
b = (12√3) * 2/√3
b = 12 * 2
b = 24
To calculate side BC;
Tan 30 = Opposite/Adjacent
Tan 30 = a/(12√3)
Tan 30 * 12√3 = a
Where Tan 30 = 1/√3
(1/√3) * 12√3 = a
12 = a
Therefore, the missing lengths in the right triangle are
AC = 24 units and BC = 12 units
