Cos ( 390)
- 4 cot (-45)
Csc (60)
Hope this helps
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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First write the equation in slope-intercept form which is more commonly known as <em>y = mx + b</em> form where the <em>m </em>or the coefficient of the x term represents the slope of the <em>b</em> or the constant term represents the y-intercept.
Subtract 2x from both sides to get <em>y = -2x - 4</em>.
I put the x term first because that's how it is in y = mx + b form.
Now we can see that the <em>b</em> or the constant term is -4.
We can write this as the ordered pair (0, -4).
Keep in mind when writing a y-intercept as an ordered pair, your x-coordinate will always be 0 in the ordered pair.
Answer: 5 feet off the ground
Step-by-step explanation:
