The proof that the Clique problem is NP-complete depends on a construction given in Theorem 34.11 (p. 1087), which reduces 3SAT
to Clique. Apply this construction to the 3SAT instance: (u+v+w)(-v+-w+x)(-u+-x+y)(x+-y+z)(u+-w+-z) Note that - denotes negation, e.g., -v stands for the literal NOT v. Also, remember that the construction involves the creation of vertices which here we denote [i,j]. The vertex [r,i] corresponds to the ith literal of the rth clause. For example, [1,2] corresponds to the occurrence of literal v in the 3SAT instance above. After performing the construction, identify from the list below the one pair of vertices that does have an edge between them. a) [2,2] and [4,3] b) [1,3] and [5,2] c) [4,3] and [5,3] d) [1,2] and [2,1]
1 answer:
You might be interested in
Answer:
Explanation:
The following piece of code is written in Java. It creates the method as requested that takes in two generic objects and compares them using the .equals() built in Java method. This method will return True if the objects are identical or False if they are not. A test case is used in the code and the output can be seen in the attached image below.
public static <T> boolean comparePerez(T a, T b) {
return a.equals(b);
}
