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Misha Larkins [42]
3 years ago
11

The proof that the Clique problem is NP-complete depends on a construction given in Theorem 34.11 (p. 1087), which reduces 3SAT

to Clique. Apply this construction to the 3SAT instance: (u+v+w)(-v+-w+x)(-u+-x+y)(x+-y+z)(u+-w+-z) Note that - denotes negation, e.g., -v stands for the literal NOT v. Also, remember that the construction involves the creation of vertices which here we denote [i,j]. The vertex [r,i] corresponds to the ith literal of the rth clause. For example, [1,2] corresponds to the occurrence of literal v in the 3SAT instance above. After performing the construction, identify from the list below the one pair of vertices that does have an edge between them. a) [2,2] and [4,3] b) [1,3] and [5,2] c) [4,3] and [5,3] d) [1,2] and [2,1]

Computers and Technology
1 answer:
ki77a [65]3 years ago
5 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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Write a program that accepts an integer value called multiplier as user input. Create an array of integers with ARRAY_SIZE eleme
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Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

void PrintForward(int myarray[], int size){

   for(int i = 0; i<size;i++){        cout<<myarray[i]<<" ";    }

}

void PrintBackward(int myarray[], int size){

   for(int i = size-1; i>=0;i--){        cout<<myarray[i]<<" ";    }

}

int main(){

   const int ARRAY_SIZE = 12;

   int multiplier;

   cout<<"Multiplier: ";

   cin>>multiplier;

   int myarray [ARRAY_SIZE];

   for(int i = 0; i<ARRAY_SIZE;i++){        myarray[i] = i * multiplier;    }

   PrintForward(myarray,ARRAY_SIZE);

   PrintBackward(myarray,ARRAY_SIZE);

   return 0;}

Explanation:

The PrintForward function begins here

void PrintForward(int myarray[], int size){

This iterates through the array in ascending order and print each array element

<em>    for(int i = 0; i<size;i++){        cout<<myarray[i]<<" ";    }</em>

}

The PrintBackward function begins here

void PrintBackward(int myarray[], int size){

This iterates through the array in descending order and print each array element

<em>    for(int i = size-1; i>=0;i--){        cout<<myarray[i]<<" ";    }</em>

}

The main begins here

int main(){

This declares and initializes the array size

   const int ARRAY_SIZE = 12;

This declares the multiplier as an integer

   int multiplier;

This gets input for the multiplier

   cout<<"Multiplier: ";    cin>>multiplier;

This declares the array

   int myarray [ARRAY_SIZE];

This iterates through the array and populate the array by i * multiplier

<em>    for(int i = 0; i<ARRAY_SIZE;i++){        myarray[i] = i * multiplier;    }</em>

This calls the PrintForward method

   PrintForward(myarray,ARRAY_SIZE);

This calls the PrintBackward method

   PrintBackward(myarray,ARRAY_SIZE);

   return 0;}

6 0
2 years ago
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