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kondaur [170]
4 years ago
9

This program will output a right triangle based on user specified height triangle_height and symbol triangle_char. (1) The given

program outputs a fixed-height triangle using a * character. Modify the given program to output a right triangle that instead uses the user-specified triangle_char character. (1 pt) (2) Modify the program to use a loop to output a right triangle of height triangle_height. The first line will have one user-specified character, such as % or *. Each subsequent line will have one additional user-specified character until the number in the triangle's base reaches triangle_height. Output a space after each user-specified character, including a line's last user-specified character. (2 pts)
Computers and Technology
1 answer:
Arturiano [62]4 years ago
4 0

Answer:

See explaination

Explanation:

triangle_char = input('Enter a character:\n')

triangle_height = int(input('Enter triangle height:\n'))

print('')

for i in range(triangle_height):

for j in range(i+1):

print(triangle_char, end = " ")

print()

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Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user
vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

   cout<<"Even Count: "<<evekount<<endl;

   cout<<"Odd Count: "<<odkount<<endl;

   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;

3 0
3 years ago
A _ shows the end of a page . ​
marta [7]

Answer:

page break shows the end of a page.

4 0
3 years ago
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Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a
yaroslaw [1]

Answer:

<em>The program doesn't use comments; See explanation section for detailed line by line explanation</em>

<em>Program starts here</em>

def lettergrade(subject,score):

     print(subject+": "+str(score))

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

     else:

           print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

<em>Line by Line explanation</em>

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

     print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

<em>This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed</em>

<em>      if score >= 90 and score <= 100:</em>

<em>            print("Letter Grade: A")</em>

<em />

<em>This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed</em>

<em>      elif score >= 80 and score <= 89:</em>

<em>            print("Letter Grade: B")</em>

<em />

<em>This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed</em>

<em>      elif score >= 70 and score <= 79:</em>

<em>            print("Letter Grade: C")</em>

<em />

<em>This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed</em>

<em>      elif score >= 60 and score <= 69:</em>

<em>            print("Letter Grade: D")</em>

<em />

<em>This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed</em>

<em>      elif score >= 0 and score <= 59:</em>

<em>            print("Letter Grade: F")</em>

<em />

<em>If input score is less than 0 or greater than 100, "Invalid Score" is printed</em>

<em>      else:</em>

<em>            print("Invalid Score")</em>

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0
3 years ago
A user is having trouble signing in to the domain from a computer that has been out of service for several months, and nobody el
Pepsi [2]

Answer:

To solve the problem, first,

a) The computer account should be reset.

b) Deactivate the computer from the domain.

c) Then, rejoin it to the domain.

Explanation:

A domain is a network that  allows different computers to function and operate from a common server. A domain may or may not be protected by a password. Setting up a domain provides additional security thereby blocking other computer networks from having access to it. When a person is experiencing difficulties in logging into a domain, there are certain things to be done to resolve the issue.

First, reset the computer account.

Secondly, deactivate the computer from the domain.

Third, Rejoin it back to the domain.

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3 years ago
What was the purpose of the Internet Architecture Board?
Nata [24]

Answer:

c to help build the internets infrastrucuter

Explanation:

6 0
3 years ago
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