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AnnZ [28]
3 years ago
13

Three consecutive integers exist where the smallest is fifteen less than twice the larger. Find the integers

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0
Consecutive integers are integers that appear one after the other. so let's call them x, x+1, and x+2.

the smallest (which is x) is 15 less than twice the larger. "the larger" is a bit unclear, but i'm assuming it is referring to the x+1 integer, because it doesn't say the "largest". so x = 2(x+1) - 15. let's try to solve for x.

x = 2(x+1) - 15
x = 2x + 2 - 15
x = 2x - 13
subtract 2x from both sides.
-x = -13
x = 13
x+1 = 14
x+2 = 15

your integers are 13, 14, and 15.
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Find the vertex of the graph of f(x)=-4(x-1)(x+5)
madreJ [45]

The vertex of the graph is (h, k) = (- 2, 36).

<h3>How to find analytically the vertex of a quadratic equation</h3>

In this question we have a quadratic equation of the form f(x) = a · (x - r₁) · (x - r₂) and we need to transform the expression into its vertex form of determine the coordinates of the vertex. First, we need to exprand the expression:

f(x) = - 4  · (x - 1) · (x + 5)

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Now we proceed to complete the square:

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The vertex of the graph is (h, k) = (- 2, 36).

To learn more on quadratic equations: brainly.com/question/17177510

#SPJ1

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