Three consecutive integers exist where the smallest is fifteen less than twice the larger. Find the integers

1 answer:

5 0

Consecutive integers are integers that appear one after the other. so let's call them x, x+1, and x+2.

the smallest (which is x) is 15 less than twice the larger. "the larger" is a bit unclear, but i'm assuming it is referring to the x+1 integer, because it doesn't say the "largest". so x = 2(x+1) - 15. let's try to solve for x.

x = 2(x+1) - 15
x = 2x + 2 - 15
x = 2x - 13
subtract 2x from both sides.
-x = -13
x = 13
x+1 = 14
x+2 = 15

your integers are 13, 14, and 15.

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