Answer:
Cindy made 3 decorations with the ribbons
Step-by-step explanation:
Since Cindy used 1/10 of a metre of ribbon to make just one decoration that she obtained by dividing 3/10 of a meter of ribbon into equal parts, then we can calculate the number of decorations that Cindy made. In this scenario, all we need is an idea on how to divide fractions and we are good to go.
If Cindy used 1/10 of a metre obtained by dividing 3/10 of a metre of ribbon to make decorations, then the number of decorations she made can be gotten by dividing 3/10 by 1/10
i.e 3/10 ÷ 1/10
= 3/10 × 10/1
= 3 decorations.
That is she used 1/10 + 1/10 + 1/10 = 3/10 to make (3 decorations).
Answer:
The answer is £52.8
Step-by-step explanation:
0.4 kilometers each week.
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
