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Sholpan [36]
3 years ago
10

Ms.Perkins needs to order art supplies for the entire school.She would like to get at least 8,000 piece construction paper has 4

95 pieces , about how many pack will she need!
Mathematics
1 answer:
Neko [114]3 years ago
3 0

Answer:

17 packs

Step-by-step explanation:

If each pack of construction paper has 495 pieces

Mrs Perkins would like to get at least 8000 pieces of construction paper

Number of Packs She will need

= Total Pieces Needed/Number of Pieces per pack

=8000/495

=16\frac{16}{99}

Now, 16 X 495 =7920 and this is less than the required numbers.

Therefore, She will need at least 17 packs in order to have a minimum of 8000 pieces pf construction paper

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12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
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\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

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⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

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\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

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2 years ago
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So (x + 2) is a factor along with (4x + 5)

3 0
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