Answer:
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.
a) Number of different samples = 20C3 = 
=1140
b) 2 good and one bad chip
Number of samples = 10C2 * 10C1 = 45 * 10 =450
c) 2 good 1 bad + 1 good 2 bad + 3 bad
Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
= 
Answer:
Step-by-step explanation:
3 : 12
Both have table of 3 in common so
1 : 4 or 1/4
4 : 64
Both have table of 4 in common
1 : 16 or 1/16
Answer:
x = 4
Step-by-step explanation:
2 + 3(3x - 6) = 5(x - 3) + 15
Expand the parenthesis:
2 + 9x - 18 = 5x - 15 + 15
Simplify:
9x - 16 = 5x
Subtract 5x from both sides:
4x - 16 = 0
Add 16 to both sides:
4x = 16
Divide both sides by 4:
x = 4
The answer for this question is 79 :)
