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3 years ago

How do you find the volume, in cubic inches of a prism?

Mathematics

1 answer:

Margaret [11]3 years ago

5 0

Answer: V= Area of the base x the height

Step-by-step explanation:

Assuming the measurements of the sides are already in inches, say the area of the base ends up being 14in and the height of the prism is 5in, multiply those numbers and your answer would be 70 inches cubed.

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Find 5 solutions to the question. Y=-1.5x+2

Black_prince [1.1K]

Answer:

☆< 《HOPE IT WILL HELP YOU》>☆

Step-by-step explanation:

Y=1.5x+2

y=1.5 (1) +2

y=1.5+2

y=3.5

y=1.5(2)+2

y=3+2

y=5

y=1.5 (3)+2

y=4.5+2

y=6.5

y=1.5 (4)+2

y=6+2

y=8

y=1.5 (5)+2

y=7.5+2

y=9.5

<h2>please mark my ans as BRAIN LIST</h2>

3 0

4 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .