Answer:
p > -18
Step-by-step explanation:
-2/3p - 4 < 8
-2/3p < 12
p > 12 x -3/2
p > -18
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
20
Step-by-step explanation:
Answer:
x = 5/4
y = 7/4
Step-by-step explanation:
The smaller triangle and the larger one are similar, so the sides are proportional.
(x+5)/5 = 10/8
x/5 + 1 = 1/4 + 1 . . . . . divide it out
x/5 = 1/4 . . . . . . . . . . .subtract 1
x = 5/4 . . . . . . . . . . . . multiply by 5
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For y, you can do exactly the same computations, replacing every instance of 5 with a 7. Then you get ...
y = 7/4
