Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92
The 90th percentile score is nothing but the x value for which area below x is 90%.
To find 90th percentile we will find find z score such that probability below z is 0.9
P(Z <z) = 0.9
Using excel function to find z score corresponding to probability 0.9 is
z = NORM.S.INV(0.9) = 1.28
z =1.28
Now convert z score into x value using the formula
x = z *σ + μ
x = 1.28 * 92 + 1028
x = 1145.76
The 90th percentile score value is 1145.76
The probability that randomly selected score exceeds 1200 is
P(X > 1200)
Z score corresponding to x=1200 is
z = 
z = 
z = 1.8695 ~ 1.87
P(Z > 1.87 ) = 1 - P(Z < 1.87)
Using z-score table to find probability z < 1.87
P(Z < 1.87) = 0.9693
P(Z > 1.87) = 1 - 0.9693
P(Z > 1.87) = 0.0307
The probability that a randomly selected score exceeds 1200 is 0.0307
Answer:
34 rolls
Step-by-step explanation:
For Frank to cover his whole ceiling, he needs paper that will cover
20 ft x 20 ft
20 x 20 = 400 ft
So, Frank needs to cover 400 ft of the ceiling. He has to split up this large need for paper into smaller rolls, because the rolls he can buy are small.
If each roll has 12 ft, we need to find how many 12-feet are in 400 feet.
To do this, we should divide
400 / 12
= 33.333
Because Frank cannot cover the whole ceiling using only 33 rolls, he has to buy an additional roll to make sure he can cover the extra area [that would be left over if he were to only buy 33 rolls, which would only cover 396 feet]
So, Frank will need to buy 34 rolls to have enough paper to entirely cover his ceiling.
So first you would divide the 9 on both sides then 6 divided by 9 would be .6 repeating so m=.6 repeating.
Answer:
yes
Step-by-step explanation: