51 degrees should be the correct answer
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
27A+81A =108
Step-by-step explanation:
Answer:
Z = 0.198877274
Step-by-step explanation:

Hence, the value of Z = 0.198877274
Answer:
line of best fit: y = -2.9114x + 46.569
Step-by-step explanation:
Plugging in your table into Excel, it turns out that y = -2.9114x + 46.569 provides a better fit of the data points into the line. Please see the attached image for details.
Hope this helps.