A room is 20 feet long, 12 feet wide, and 10 feet high. What is the maximum distance from one corner to another
2 answers:
Answer:
25.4 ft
Step-by-step explanation:
Let D1 be the distance from one corner to the diagonally opposite one and D2 be the diagonal distance from one corner to the ceiling.
D1² = 20² + 12²
D2² = D1² + 10² Substitute the value of D1²
D2² = 20² + 12² + 10²
D2² = 400 + 144 + 100
D2² = 644
D2 = √(644)
D2 = 2√(161)
D2 ≈ 25.4 ft
Answer:
25.38
Step-by-step explanation:
Its a 3-D block, so you have to find the distance from on corner to the opposite corner of the roof, but first find the distance from corner to corner on the floor.
20^2+12^2=c^2
400+144=544=c^2
c=
then find corner of floor to opposite roof corner.
100+544=644=c^2
c=
so its about 25.38 feet
You might be interested in
Answer:
the value of such that there is no solution to the equation is
.
Step-by-step explanation:
Let first simplify the expression presented on statement. The equation has no solution if and only if is eliminated in the process and an absurd is the result (i.e.
).
To obtain an absurd, we need that . Hence, the value of
such that there is no solution to the equation is:
Let prove the certainty of the result. We find that an absurd exist: ()
Answer:
See Explanation
Step-by-step explanation:
Line l is bisector of MO... (given)
Thus Proved