A room is 20 feet long, 12 feet wide, and 10 feet high. What is the maximum distance from one corner to another
2 answers:
Answer:
25.4 ft
Step-by-step explanation:
Let D1 be the distance from one corner to the diagonally opposite one and D2 be the diagonal distance from one corner to the ceiling.
D1² = 20² + 12²
D2² = D1² + 10² Substitute the value of D1²
D2² = 20² + 12² + 10²
D2² = 400 + 144 + 100
D2² = 644
D2 = √(644)
D2 = 2√(161)
D2 ≈ 25.4 ft
Answer:
25.38
Step-by-step explanation:
Its a 3-D block, so you have to find the distance from on corner to the opposite corner of the roof, but first find the distance from corner to corner on the floor.
20^2+12^2=c^2
400+144=544=c^2
c=
then find corner of floor to opposite roof corner.
100+544=644=c^2
c=
so its about 25.38 feet
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Step-by-step explanation:
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Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:
The points are (3,5) and (-2,1):
The equation is now:
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The required equation of the line is: