A room is 20 feet long, 12 feet wide, and 10 feet high. What is the maximum distance from one corner to another
2 answers:
Answer:
25.4 ft
Step-by-step explanation:
Let D1 be the distance from one corner to the diagonally opposite one and D2 be the diagonal distance from one corner to the ceiling.
D1² = 20² + 12²
D2² = D1² + 10² Substitute the value of D1²
D2² = 20² + 12² + 10²
D2² = 400 + 144 + 100
D2² = 644
D2 = √(644)
D2 = 2√(161)
D2 ≈ 25.4 ft
Answer:
25.38
Step-by-step explanation:
Its a 3-D block, so you have to find the distance from on corner to the opposite corner of the roof, but first find the distance from corner to corner on the floor.
20^2+12^2=c^2
400+144=544=c^2
c=
then find corner of floor to opposite roof corner.
100+544=644=c^2
c=
so its about 25.38 feet
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. We are asked to find the solution of our given system of equations.
The solution of our given system of equations will be the point, where both lines will intersect.
To find intersection point, we will equate both equations as:
Now we will substitute in equation
and solve for y.
Therefore, the point is the solution of our given system of equations.
We can verify our answer by graphing both equations.
