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2 years ago

Find the sum of the series using the formula

Mathematics

1 answer:

Gnom [1K]2 years ago

8 0

Answer:

We have a1 = 27 and r = 3 (because 27:9 = 3; 9:3 = 3; 3:3 = 1);

Then s = 27 / (1 - 3) ;

Finally, s = - 27 / 2;

Step-by-step explanation:

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Soloha48 [4]

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3 years ago

G(x)=x+5/2x+1 find g(z+2)

ra1l [238]

Answer:

g(z+2)=(z+7)/(2z+5)

Step-by-step explanation:

g(x)=(x+5)/(2x+1)

Replace x with z+2

g(z+2)=(z+2+5)/(2*(z+2)+1)

Combine like terms

g(z+2)=(z+7)/(2z+4+1)

g(z+2)=(z+7)/(2z+5)

5 0

3 years ago

I'm still stuck on this one

Evgesh-ka [11]

The answer would be -4.5/5. You would have to plot the number in between -2 and - 1 4/5. Hope this helps!

7 0

3 years ago

Raj, Amit, Parul, and Lara were asked to find the volume of the following cones.

vlabodo [156]

Answer:

Option C is correct Parul is closest to 9 pi centimeters cubed!!!

Have a Great Day!!!!

5 0

3 years ago

Read 2 more answers

A pyramid has a square base with sides of length s. The height of the pyramid is equal to - of the length of a side on the base.

Vera_Pavlovna [14]

<h3><u>Question:</u></h3>

A pyramid has a square base with sides of length s. The height of the pyramid is equal to 1/2 of the length of a side on the base. Which formula represents the volume of the pyramid?

<h3><u>Answer:</u></h3>

<em><u>The formula represents the volume of the pyramid is:</u></em>

$V=\frac{1}{6}s^3$

<h3><u>Solution:</u></h3>

<em><u>The volume of square pyramid is given by formula:</u></em>

$V = \frac{1}{3} a^2h$

Where, "h" is the height of pyramid

"a" is the length of side of base

Here given that, pyramid has a square base with sides of length s

Therefore,

a = s

The height of the pyramid is equal to 1/2 of the length of a side on the base

$h = \frac{1}{2} \times s\\\\h = \frac{s}{2}$

<em><u>Thus the volume of pyramid becomes:</u></em>

$V = \frac{1}{3} \times s^2 \times \frac{s}{2}\\\\V = \frac{s^3}{6}$

$\boxed{V=\frac{1}{6}s^3}$

Thus the formula represents the volume of the pyramid is $\frac{s^3}{6}$

5 0

3 years ago