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Flura [38]
3 years ago
5

the new dolphin tank at the aquarium has a radius of 75 feet and a height of 20 feet. what is the volume of the dolphin tank? ro

und to the nearest tenth. use 3.14 for pie
Mathematics
2 answers:
Semmy [17]3 years ago
6 0
Solutions 

 V=3.14r^2 * 20 

Radius = 75 

3.14 * 75^2 * 20 

3.14 * 5625 * 20 
 
17662.5 * 20 

= 353,250 feet cubed  



ohaa [14]3 years ago
3 0

Answer:

353,250.0 cubic feet

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What is the value of x and the length of DGE
pogonyaev

Answer:

X=3

Line DG =32

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3 years ago
In the sequence 400, 200, 150, 75, 25...... what number comes next
Scorpion4ik [409]

Answer:

The next term in the sequence = -175

Step-by-step explanation:

Here, the given sequence is : 400, 200, 150, 75, 25...

Now here, in the given sequence,

First Term - Second Term = 400 - 200 = 200

Second Term -   Third Term   =  200  - 150  = 50

Third term  - Fourth Term  = 150 - 75   = 75

Fourth term - Fifth term = 75 - 25 =  50

So, following this pattern,

Fifth Term - Sixth term = 200

Or, 25 - Sixth Term = 200

or, Sixth term  =  25 - 200  = - 175

Hence, the next term in the sequence = -175

4 0
3 years ago
The graph of
ratelena [41]

Answer:

Positive and negative intervals on a graph

Step-by-step explanation:

The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero). The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). hope this helps you :)

3 0
3 years ago
Read 2 more answers
Solve the following ODE's: c) y* - 9y' + 18y = t^2
Nastasia [14]

Answer:

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = C_1e^{3t}+C_2e^{6t}

now calculating P.I.

P.I. = \frac{t^2}{D^2 - 9D +18}

P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

hence the complete solution

y = C.F. + P.I.

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

7 0
3 years ago
The congruence theorem that can be used to prove △LON ≅ △LMN is SSS. ASA. SAS. HL.
Zinaida [17]

Answer:

The correct option is SSS (Side-Side-Side) Theorem

Step-by-step explanation:

The question is incomplete because the diagrams of ΔLON and ΔLMN are not given. I have attached the diagram of both triangles below for better understanding of the question.

Consider the diagram attached below. We have to find the congruence theorem which can be used to prove that ΔLON ≅ ΔLMN

We can see in the diagram that both triangle have a common side that is LN. It means 1 side of both triangles is congruent because LN≅LN

Consider the sides ON and MN. Both side have a single bar on them, which means that it is given that both of these side are congruent. Hence ON≅MN

Consider the sides LO and LM. Both side have a double bars on them, which means that it is given that both of these side are also congruent. Hence LO≅LM

SSS theorem states that if all sides of the triangles are congruent, then the triangles themselves are also congruent, which is the same case in this question

4 0
3 years ago
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