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4 years ago

How to solve mean media and mode

1 answer:

6 0

You can solve mean by adding up all the numbers then dividing it by the number of numbers there are.

You can solve the median by putting all of the numbers in order and then crossing off one in the beginning then crossing off one at the end. You can continue that until you get to one number in the middle.

You can solve the mode by looking for the most frequent number. That's the mode. You can remember that by looking at the MO and remember most often.

I hope this helps :-)

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Which point is located at (-3,6) A) A B) B C) C D) D

Andrej [43]

Answer is A

Step-by-step explanation:

Go over to the left 3 times then up 6

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3 years ago

7,243 ÷ 4. What is the remainder?

Sveta_85 [38]

Divested using long division
1810 r 3

4 0

4 years ago

Jake is taking four of his friends to dinner. At the restaurant, a meal, side item, dessert, and drink cost $5.60. The first dri

KonstantinChe [14]

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3 years ago

121 is increased to 321 percent of change

valina [46]

Answer: This is the percentage increase.

Step-by-step explanation:

265.28925619834706%

7 0

3 years ago

Plz read and answerrrrrrrrrrr

natulia [17]

Answer:

16.7%.

Step-by-step explanation:

There are initially $24 + 15 + 8 = 47$ pencils in the bag.

Take a pencil out of this bag of 47 pencils. 15 out of the 47 pencils blue. Let $A$ represent the event of getting a blue pencil on the first pick. The probability of getting a blue pencil is:

$\displaystyle P(A) = \frac{15}{47}$ .

There are now $47 - 1 = 46$ pencils left in the bag. However, given that the first pencil removed from the bag is blue, the number of red pencils in the bag will still be 24. Take another pencil out of this bag of 46 pencils. Let $B$ represent the event of getting a red pencil on the second pick. The possibility that the second pencil is red given that the first pencil is blue will be:

$\displaystyle P(B|A) = \frac{24}{46}$ .

The question is asking for the possibility that the first pencil is blue and the second pencil is red. That is:

$\displaystyle P(A\cap B) = P(A) \cdot P(B|A) = \frac{15}{47}\times \frac{24}{46} = 0.166512 \approx 16.7\%$ .

5 0

4 years ago