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3 years ago

How to solve mean media and mode

1 answer:

6 0

You can solve mean by adding up all the numbers then dividing it by the number of numbers there are.

You can solve the median by putting all of the numbers in order and then crossing off one in the beginning then crossing off one at the end. You can continue that until you get to one number in the middle.

You can solve the mode by looking for the most frequent number. That's the mode. You can remember that by looking at the MO and remember most often.

I hope this helps :-)

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HELP++++++++++++++++++++++++

lys-0071 [83]

Answer:

ASA

ΔFGH ≅ ΔIHG ⇒ answer B

Step-by-step explanation:

* Lets revise the cases of congruence

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

leg of the 2nd right angle Δ

* Lets prove the two triangles FGH and IHG are congruent by on of

the cases above

∵ FG // HI and GH is transversal

∴ m∠FGH = m∠IHG ⇒ alternate angles

- In the two triangles FGH and IHG

∵ m∠FHG = m∠IGH ⇒ given

∵ m∠FGH = m∠IHG ⇒ proved

∵ GH = HG ⇒ common side

∴ ΔFGH ≅ ΔIHG ⇒ ASA

* ASA

ΔFGH ≅ ΔIHG

3 0

3 years ago

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$

8 0

3 years ago

If (x, -3) is on the line described by f(x)=-x+8, what is the value of x

qwelly [4]

The value of <u>x</u> that the given point of the function is 11.

<h3>Linear Function</h3>

An equation can be represented by a linear function. The standard form for the linear equation is: y= ax+b , for example, y=5x+3. Where:

a= the slope

b= the constant term that represents the y-intercept.

For the previous example: a=5 and b=3.

The question gives a point (x , -3) of a function f(x)= -x+8. Therefore, you can write

-3=-x+8

x=8+3

x=11

Thus, the x-coordinate is equal to 11.

Read more about the linear equations here:

brainly.com/question/2030026

#SPJ1

4 0

1 year ago

The market equilibrium point for a product is reached when 12000 units are produced and sold at $27 per unit. The manufacturer w

mamaluj [8]

If the equilibrium is such that only 12000 units are sold for $27, then the total earnings from the given scenario is $324,000. The supply equation would then be,
supply: 324000 = 6p ; p = 324000/6 = 54000
demand: 324000 = 69p ; p = 324000/69 = 4695.65 ≈ 4696

8 0

3 years ago

The diameter of a beach ball is 10 inches. How many cubic inches of air can the beach ball hold? Use 3.14 for Pi. Round to the n

Nata [24]

Answer:

523.3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers