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Lady_Fox [76]
3 years ago
11

Mr. Cantu opened an account with a deposit of $2,000.

Mathematics
2 answers:
shepuryov [24]3 years ago
6 0

Answer:

8.25% is the interest rate on this account

Lesechka [4]3 years ago
3 0
I think the answer is A
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Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl
kompoz [17]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at \alpha =0.001 is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

     The population mean is  \mu =  18

     The sample size is  n  =  15

      The sample mean is  \=  x  =  19

      The standard deviation is  \sigma =  1.7

      The level of significance is  \alpha  =  0.001

The null hypothesis is  H_o:  \mu = 18

The  alternative hypothesis is  H_a :  \mu > 18

 The critical value of the level of significance from the normal distribution table is    

         Z_{\alpha } =  3.290527

The test hypothesis is mathematically represented as

           t =  \frac{\= x  -  \mu }{ \frac{\sigma}{ \sqrt{n} } }

substituting values  

         t =  \frac{ 19  - 18}{ \frac{1.7}{ \sqrt{15} } }

         t =  2.28

Looking at the value of  t and  Z_{\alpha } we can see that t <  Z_{\alpha } so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

     

       

3 0
3 years ago
I need a hand please
bearhunter [10]
The answer would be 2/7, because 3 and 5 are the only factors of 15. 2/7 which is about 29 percent.
8 0
3 years ago
Larry reads that 1 out of 4 eggs contains salmonella bacteria, so he never uses more than 3 eggs in cooking. If eggs do or don't
aleksley [76]

Answer:

57.8125% or approx. 57.8%

Step-by-step explanation:

There is a 1/4, or 25%, or 0.25 chance that an egg has salmonella.

Thus, there is a 75%, or 0.75 chance that an egg DOESN'T contain salmonella.

Let's find the probability that all 3 of Larry's eggs are free from salmonella. Larry would have to hit that 75% chance 3 times in a row. The chance of that happening is:

0.75 * 0.75 * 0.75 = 0.75^3 = 0.421875

From this, we can deduce that if there is a 0.421875 (42.1875%) chance that all eggs are safe to eat, there must be a...

1 - 0.421875 = 0.578125

...0.578125 (57.8125%) chance that 1 or more of Larry's eggs do have salmonella.

Answer: approx. 57.8% or 57.8125%

7 0
3 years ago
Suppose a school has 20 classes: 16 with 25 students in each, three with 100 students in each, and one with 300 students for a t
expeople1 [14]
16 classes have 25 students each which EQUALS a total of 400 students and 3 classes which each have 100 students each which EQUALS a total of 300 and 1 class has a total of 300 students and the total number of students is 1000
3 0
3 years ago
What is 35÷110 equal
Thepotemich [5.8K]
0.32 is the answer you are looking for.
3 0
3 years ago
Read 2 more answers
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