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Rainbow [258]
3 years ago
7

Slope : - 9/7 point : ( -7,4 )

Mathematics
1 answer:
dolphi86 [110]3 years ago
7 0
To form an equation with the given information, we use the formula :

y = mx + b, m being the slope and b being the y-intercept.

Since it is given that the slope is -9/7, we substitute m with -9/7.

y = -9/7x + b

To find b, we will substitute the known coordinates into the equation :
At point (-7 , 4), x = -7, y = 4

4 = -9/7 (-7) + b
4  = 9 + b
b = 4 - 9
b = -5

Now we know that b = -5, we will substitute b = -5 into the equation that we found earlier, y = -9/7 x + b :

y = - 9/7x - 5

To make it more readable, we can multiply the equation by 7:
7y = -9x - 5
7y + 9x + 5 = 0

-----------------------------------------------------------
Answer : 7y + 9x + 5 = 0
-----------------------------------------------------------
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5 0
3 years ago
If M is the midpoint of XY, find the coordinates of X if M(-3,-1) and Y(-8,6)
vova2212 [387]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
X&({{ a}}\quad ,&{{ b}})\quad 
%  (c,d)
Y&({{ -8}}\quad ,&{{ 6}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)

\bf \left( \cfrac{-8+a}{2}~,~\cfrac{6+b}{2} \right)=\stackrel{M}{(-3,-1)}\implies 
\begin{cases}
\cfrac{-8+a}{2}=-3\\\\
-8+a=-6\\
\boxed{a=2}\\
----------\\
\cfrac{6+b}{2}=-1\\\\
6+b=-2\\
\boxed{b=-8}
\end{cases}
5 0
3 years ago
Show that 5x^2 + 2x - 3 < 0 can be written in the form | x + 1/5 | < 4/5
Sliva [168]

Step-by-step explanation:

First let solve the inequality

5 {x}^{2}  + 2x - 3 < 0

Factor by grouping

5 {x}^{2}  + 5x - 3x - 3 < 0

5x(x + 1) - 3(x + 1)

So the factor are

(5x - 3)(x + 1)

So the factor are

x =  \frac{3}{5}

and

x =  - 1

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

|x - b|   <  c

works as

b is the midpoint between 2 roots. And c is the

|x + b|  = c

We know that the midpoint between both roots is-1/5.

so

|x - ( -  \frac{1}{5} )|  < c

|x +  \frac{1}{5} |  < c

Let use roots 3/5

| \frac{3}{5}  +  \frac{1}{5} |  =  \frac{4}{5}

-1 works as well.

| - 1 +  \frac{1}{5} |  =   |   -   \frac{4}{5} |  =  \frac{4}{5}

So the absolute value equation is

|x +  \frac{1}{5} |  <  \frac{4}{5}

8 0
3 years ago
A line goes through the points (-4,6) and (-2,3). A line perpendicular to<br> that line is:
gulaghasi [49]

Answer: A line with a slope of 2

Step-by-step explanation: the slope of the line is -1/2 so the negative reciprcal of the slope is 2 (It would be perpendicular to it)

i used m=y2-y2/x2-x1 to figure ou the slope and -(x/y) as the negative reciprcal for the perpendicular line.

5 0
3 years ago
Find f(-2). <br> (I have the answer, I just don’t know how to do it)
34kurt

Answer:

You plug in -2 into where it says x, then you solve.


3 0
3 years ago
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