Question

In the diagram shown, chords AB and CD intersect at E. The measure of (AC) ̂ is 120°, the measure of (DB) ̂ is (2x)° and the measure of ∠AEC is (4x)°. What is the degree measure of ∠ AED?

Answer 1

Answer:

The measure of angle < AED is $100\°$

Step-by-step explanation:

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.

so

$m$

substitute the values and solve for x

$4x=\frac{1}{2}(120\°+2x)$

$8x=(120\°+2x)$

$8x-2x=120\°$

$6x=120\°$

$x=20\°$

$m$

$m$ -----> by supplementary angles

substitute value

$80\°+m$

$m$