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Alex17521 [72]
3 years ago
11

6(4x+2)=3(8x+4) ?? please help asap

Mathematics
2 answers:
Mumz [18]3 years ago
6 0
24x + 12 = 24x + 12
I.M.S
Infinitely Many Solutions
nasty-shy [4]3 years ago
4 0
6(4x + 2) = 3(8x + 4)

Reorder the terms:
6(2 + 4x) = 3(8x + 4)
(2 * 6 + 4x * 6) = 3(8x + 4)
(12 + 24x) = 3(8x + 4)

Reorder the terms:
12 + 24x = 3(4 + 8x)
12 + 24x = (4 * 3 + 8x * 3)
12 + 24x = (12 + 24x)

Add '-12' to each side of the equation.
12 + -12 + 24x = 12 + -12 + 24x

Combine like terms: 12 + -12 = 0
0 + 24x = 12 + -12 + 24x
24x = 12 + -12 + 24x

Combine like terms: 12 + -12 = 0
24x = 0 + 24x
24x = 24x

Add '-24x' to each side of the equation.
24x + -24x = 24x + -24x

Combine like terms: 24x + -24x = 0
0 = 24x + -24x

Combine like terms: 24x + -24x = 0
0 = 0

Solving
0 = 0
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6 0
3 years ago
I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th
stellarik [79]

Answer:

The number of once is 9.1  

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18             .........1

100 × H + 1 × O = 900          ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴   H = \frac{882}{99}

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e  O = 18 - 8.9

∴    O = 9.1

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Hence The number of once is 9.1  and The number of hundreds is 8.9

Answer

4 0
4 years ago
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