Answer:
<u>The additional 1.3% of increase in the annual interest rate that Jack is receiving in his savings account, from 2.8% to 4.1%, represent an increase of 46.42%.</u>
Step-by-step explanation:
Jacks's savings account annual interest rate before = 2.8%
Jacks's savings account annual interest rate after the increase = 4.1%
Difference of the two rates = 4.1% - 2.8% = 1.3%
How much percentage is that additional 1.3% from the rate before the increase?
(1.3 * 100)/ 2.8 = 130/2.8 = 46.42%
<u>The annual interest rate increased by 46.42% from the previous annual interest rate.</u>
Answer:
Step-by-step explanation:
0.0000345
Answer:
2y² -4y +5
Step-by-step explanation:
First you need to find the sum of y²+5y-1 and 3y²-2y+4
(y²+5y-1) + (3y²-2y+4) => y²+3y²+5y-2y-1+4
=4y²+3y+3
Next is to subtract 2y²+7y-2 from the sum calculated above in order to find the algebraic expression asked in the exercise
4y²+3y+3 -(2y²+7y-2) => 4y²-2y²+3y-7y+3+2
=2y² -4y +5
Therefore, the algebraic expression asked must be 2y² -4y +5
I believe the answer is football.