Question

Mary weighs n kg while her sister weighs 15 kg less. How many times is Mary heavier than her sister?

Answer 1

For this case we have to:

n: Represents the weight of Mary in Kg.

If your sister weighs 15 kg less we have:

$y = n-15$

Where "y" represents the weight of his sister in kg.

To find how many times Mary is heavier than her sister, we must divide Mary's weight by her sister's weight.

We have then:

$N= \frac{n}{n-15}$

Answer:

Mary is $N= \frac{n}{n-15}$ times heavier than her sister.

Answer 2

Answer:

Mary weighs$\frac{n}{(n-15)}$heavier than her sister.

Explanation:

As we have given the data  in the question that  

Weight of marry = n kg

Weight of Marry sister = n-15 kg

Let Marry be ‘K' times heavier than her sister then it means that  

K=$\frac{n}{(n-15)}$

And we can write the above equation as

K(n-15) = n

K=$\frac{n}{(n-15)}$

which completely explains the above statement that Weight of the marry is K times the weight of her sister.

So the correct answer is  K=$\frac{n}{(n-15)}$