What are complex numbers?
2 answers:
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Answer: 4
There are three different ways to find the remainder. Since I don't know which lesson you are working on, I will show you all three methods.
<u>Long Division:</u>
<u>3x + 7 </u>
2x - 1 ) 6x² + 11x - 3
- <u>(6x² - 3x)</u> ↓
14x - 3
- (<u>14x - 7)</u>
4
<u>Synthetic Division:</u>
2x - 1 = 0 ⇒ x =
| 6 11 -3
<u>| ↓ 3 7</u>
6 14 4
<u>Remainder Theorem:</u>
2x - 1 = 0 ⇒ x =
f(x) = 6x² + 11x - 3
f() = 6(
)² + 11(
) - 3
= 6() +
- 3
= +
-
=
= 4