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allochka39001 [22]
3 years ago
8

PLSSS HELPPPP!!! Find all real zeros and complexof each equation f(x)=(x^2+4)(x^2-9)

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

x = ± 3, x = ± 2i

Step-by-step explanation:

Given

f(x) = (x² + 4)(x² - 9)

To find the zeros let f(x) = 0, that is

(x² + 4)(x² - 9) = 0

Equate each factor to zero and solve for x

x² - 9 = 0 ( add 9 to both sides )

x² = 9 ( take the square root of both sides )

x = ± \sqrt{9} = ± 3

x² + 4 = 0 ( subtract 4 from both sides )

x² = - 4 ( take the square root of both sides )

x = ± \sqrt{-4} = ± \sqrt{4(-1)} = ± \sqrt{4} ×\sqrt{-1} = ± 2i

Thus zeros are

x = - 3, x = 3 ← real

x = - 2i, x = 2i ← complex

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