Answer:
c. x = -1/15
Step-by-step explanation:
5/2x - 1/3 = -1/2 [multiply the whole equation by 6 (lowest common denom)
15x - 2 = -3 [add 2 on both sides of equation
15x = -1 [divide both sides by 15 to isolate x]
x = -1/15
The probability that a high school student in in the marching band is 0.47
so,
The probability that a student plays a varsity sport is 0.32
so,
the probability that a student is in the marching band and plays a varsity sport is 0.24
so, we get
P(M∩V)=0.24
a student plays a varsity sport if we know she is in the marching band
so,
P(V|M)=(P(V∩M))/(P(M))
now, we can plug values
and we get
So,
the probability that a student plays a varsity sport if we know she is in the marching band is 0.51063......Answer
Y = - 10x has a negative slope, m = -10, and a y-intercept of (0, 0).
The graph includes the following points:
{(-2, 20), (-1, 10), (0, 0), (1, -10), (2, -20)}.
Attached is a screenshot of the graph, where it includes the y-intercept crossing along the point of origin, (0, 0).
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The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate
together they represent a point, which is the center
So (h,k) is (x,y)
The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola.