1.Given point (-6, -3) and a slope of 4, write an equation in point-slope form.

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

Step-by-step explanation:

1) c

2) c

use the value of slope and the coordinates and substitute in the equation of line.

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The measure of position called the midquartile of a data set is found using the formula StartFraction Upper Q 1 plus Upper Q 3 O

irinina [24]

Answer:

35.25

Step-by-step explanation:

Give the data set:

23 37 49 34 35 41 40 26 32 22 38 42

We are expected to calculate the midquartile of the given data set.

22 23 26 32 34 35 37 38 40 41 42 49

First step is to find the lower quartile which comprises of

22 23 26 32 34 35

Here the Q1 is (26+32)/2 = 58/2= 29

Second step to find the upper quartile which comprises of

37 38 40 41 42 49

Here the Q3 is (40+41) /2 = 81/2 = 41.5

Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5

= (29+41.5)/2

= (70.5) /2 = 35.25

8 0

3 years ago

Can some one help me plz trying to figure out? Need help ASAP

zloy xaker [14]

Answer:

$a. = -35 \\ b. = 9a + 1 \\ c. = -35$

Step-by-step explanation:

$a. \\ = > \: 7a - 1 + 2a + 2 \\ \\ = > 7( - 4) - 1 + 2( - 4) + 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (a = - 4) \\ \\ = > - 28 - 1 - 8 + 2 \\ \\ = > - 37 + 2 \\ \\ = > - 35 \\ \\ \\ b. \\ = > 7a - 1 + 2a + 2 \\ \\ = > 7a + 2a - 1 + 2 \\ \\ = > 9a + 1 \\ \\ \\ c. \\ = > 9a + 1 \\ \\ = > 9( - 4) + 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (a = - 4) \\ \\ = > - 36 + 1 \\ \\ = > - 35$