Answer: 0.0516
Step-by-step explanation:
Given : The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of
.
The probability mass function for Poisson distribution:-
For x= 15 and
, we have

Hence, the probability that exactly 15 defective components are produced in a particular day = 0.0516
Answer:
6.3/2.5=2.52
Step-by-step explanation:
Answer:
<x = 20°
Step-by-step explanation:
<x = 1/2(arc UT - arc SV)
<x = 1/2(65° - 25°)
<x = 1/2 (40°)
<x = 20°
Answer:
No. of boxes = 10
Oranges per box = 56
Total no. of oranges = 56*10=560
No. of bad oranges = 560/40= 14
(i) Probability of bad orange = 14/560 = 1/40
(ii) no of oranges expected to be bad = 14 ( found above)
Hope it helps.............. :)