Question

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution. (7, -3) and (4, -8)

Answer 1

Answer: $5x-3y=44$

Step-by-step explanation:

We know that , the equation of a line that passes through (a,b) and (c,d) is given by :_

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Standard form of equation of line = $Ax+By=C$

Given points =  (7, -3) and (4, -8)

Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -

$(y-(-3))=\dfrac{-8-(-3)}{4-7}(x-7)$

$(y+3)=\dfrac{-8+3}{-3}(x-7)$   [∵ (-)(-)=(+)]

$(y+3)=\dfrac{-5}{-3}(x-7)$

$(y+3)=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$9+35=5x-3y$

$44=5x-3y$

Or $5x-3y=44$

Hence, the required equation :-$5x-3y=44$