If the first roll is a 4, the possibilities to add less than 8 are that the second cube roll is 1, 2 or 3.
These are 3 different events out of 6 possilbe ones, which is 3 / 6 = 1 / 2; i.e. half of times.
Then the answer is the first option: 1 / 2
Answer:
Step-by-step explanation:
We are looking for P(58 < x < 64). We need to find the percentage to the left of the z-scores for each of these numbers. To find the z scores, use the formula:

which gives us a z-score of -1. The percentage of numbers to the left of a z-score of -1 is .1586553
Now for the other z-score:
which gives us a z-score of .5. The percentage of numbers to the left of a z-score of .5 is .69146246
The lower percentage subtracted from the higher gives the area in question:
.69146246 - .1586553 = .53280716, or as a percentage, 53.3%, choice A.
Answer: i believe its a x=2
Answer:
a)
=4.63 md=4.55 mo= 1.9 b) Sample Standard Deviation≈ 2.58 Coefficient of Variation=55.72% Sample Range=6.9
Step-by-step explanation:
a)
<u>Mean</u>

For the <u>Median</u>, we have to order the entries. So, ordering it goes:
1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8
Since we have even entries 
mode
The mode for this data 1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8 is 1.9
b)
<u>Sample Standard Deviation</u>
Here it is the formula to calculate it:

<u>Coefficient of Variation</u>
CV is the quocient between sample Standard deviation over Mean and it is used to make comparisons.

<u>Range</u>
The difference between the highest and the lowest value of this sample
8.8-1.9=6.9
Answer:
34.43
Step-by-step explanation:
A differential of length in terms of t will be ...
dL(t) = √(x'(t)^2 +y'(t)^2)
where ...
x'(t) = 4cos(4t)
y'(t) = 7cos(7t)
The length of c(t) will be the integral of this differential on the interval [0, 2π].
Dividing that interval into 10 equal pieces means each one has a width of (2π)/10 = π/5. The midpoint of pieces numbered 1 to 10 will be ...
(π/5)(n -1/2), so the area of the piece will be ...
sub-interval area ≈ (π/5)·dL((π/5)(n -1/2))
It is convenient to let a spreadsheet or graphing calculator do the function evaluation and summing of areas.
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The attachment shows the curve c(t) whose length we are estimating (red), and the differential length function (blue) we are integrating. We use the function p(n) to compute the midpoint of the sub-interval. The sum of sub-interval areas is shown as 34.43.
The length of the curve is estimated to be 34.43.