AB and BC form a right angle at their point of intersection. This means AB is perpendicular to BC.
We are given the coordinates of points A and B, using which we can find the equation of the line for AB.
Slope of AB will be:

Using this slope and the point (2,1) we can write the equation for AB as:

The above equation is in slope intercept form. Thus the y-intercept of AB is 4/3.
Slope of AB is -1/6, so slope of BC would be 6. Using the slope 6 and coordinates of the point B, we can write the equation of BC as:
y - 1 = 6(x - 2)
y = 6x - 12 + 1
y = 6x - 11
Point C lies on the line y = 6x - 11. So if the y-coordinate of C is 13, we can write:
13 = 6x - 11
24 = 6x
x = 4
The x-coordinate of point C will be 4.
Therefore, the answers in correct order are:
4/3 , 6, -11, 4
Answer:
The vertex of the parabola is at equal distance between focus and the directrix. If F is the focus of the parabola, V is the vertex and D is the intersection point of the directrix and the axis of symmetry, then V is the midpoint of the line segment ¯FD
Step-by-step explanation:
answer 3rd
Answer:
Because if it is zero, then it is multiplied the variable and it will be zero. For example if I had 0x(squared) + x, it would just be x because zero times any number is zero. Looking at the problem, I would assume it was quadratic because it had x squared, but it isn't because there are 0 x squared values.
Step-by-step explanation:
Answer:
is there more info? I don't think this can be solved with given numbers could you take a more zoomed out photo?
Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis.
I believe this is the answer