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4 years ago

Someone give me the answer thanks

Mathematics

2 answers:

defon4 years ago

8 0

When you plug 2 in for x, the equation equals 1. The easiest way to go about this is solving the numerator then the denominator. The denominator was equal to 3 and the numerator was equal to 3, thus making 3/3. This equals 1.

Goshia [24]4 years ago

3 0

((-2x2)/4) + 4(2-1)) / 4-1
=3/3
=1

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

o-na [289]

Answer:

The answer will just be 125b^4

Step-by-step explanation:

Basically multiply 5 by 5 by 5 and then count all of the b’s (4 b’s) and add it to the product as an exponent

Final answer: 125b^4

6 0

3 years ago

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

4 years ago

HELP ME PLS I WILL GIGE BRAINLIEST

vazorg [7]

Answer:

C and D

Step-by-step explanation:

2x^2 + 7x + 6

(2x + 3)(x+2)

x = -3/2 = -1.5

x = -2

3 0

3 years ago

Given the function f(a) = 5a + 14, solve for f(a) = 0. Give an exact answer; do not round.

Ket [755]

Answer:

a = 14

Step-by-step explanation:

Step 1: Write out your problem

f (a) = 5a + 14 | f (a) = 0

Step 2: Solve

f (a) = 5 (0) + 14 , Input a.

f (a) = 0 + 14 , 5 x 0 = 0

(a) = 14 , 0 + 14

a = 14

5 0

3 years ago

Read 2 more answers

Malika knows that 230 - 39 = 191.

Alex

Answer:

she has to minus just as she did before.

Step-by-step explanation:

230-39=191

233-42=191

the reason as to why they have the same answer is because it was first 230 but it later it was 233.so just minus as before.hope it will help goodbye

4 0

3 years ago

Read 2 more answers