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lara31 [8.8K]
2 years ago
13

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

Mathematics
1 answer:
o-na [289]2 years ago
6 0
Answer:

The answer will just be 125b^4

Step-by-step explanation:

Basically multiply 5 by 5 by 5 and then count all of the b’s (4 b’s) and add it to the product as an exponent

Final answer: 125b^4
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Write each as a decimal.Round to the thousands place​
max2010maxim [7]

Answer:

2) 0.3

4) 0.09

6) 0.65

8) 4.45

Step-by-step explanation:

hope this helps ;)

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2 years ago
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For a quadratic function, which characteristics of its graph is equivalent to the zero of the function? a) y-intercept b) maximu
Sonja [21]

Answer:

d) x-intercept

Step-by-step explanation:

The zeros of a function are the values of x that make y = 0.

Thus, they are the points where the graph crosses the x-axis, that is, the x-intercepts.

a) is wrong. the y-intercept is simply the value of y when x = 0.

b) and c) are wrong. A quadratic can have only one maximum or one minimum; it can't have both. And they are not zeros except in the special case of y = ±ax².

The diagram below is the graph of y = x² + 3x - 46. It shows the zeros at x = -23 and x = 20. The minimum and the y-intercept are not zeros of the function.

3 0
3 years ago
Which unit rate is the lowest price per ounce? Choice A: 15 ounces of chocolate chips for $2.49 Choice B: 20 ounces of chocolate
iris [78.8K]
2.49/15 = 0.166
3.32/20 = 0.166

they both cost the same per oz
3 0
3 years ago
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Choose the equation that represents the line that passes through the point (-1, 6) and has a slope of (-3).
expeople1 [14]
It’s c bro yes it is
8 0
2 years ago
The value, V (t), in dollars, of a stock t months after it is purchased is modeled by the following equation.
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:V(t)= 42(1-e ^{1.5t} ) +36 is given value in dollars of a stock in t months after it is purchased.

a) Substitute 1 for t

V(1) = 42(1-e^{-1.5} )+36 \\=67.852\\=67.85

V(12) = V(1) = 42(1-e^{-1.5*12} )+36 \\=77.00

b) Find derivative for V

V'(t) = 42(-1.5) e^{-1.5t} )\\\\=-63e^{-1.5t}

c) When V(t) = 75

V(t)=75= 42(1-e ^{1.5t} ) +36\\1-e ^{1.5t=0.9286\\=-2.639

d) As t tends to infinity, exponent being in negative t tends to 0

So V tends to 42(1-0)+36 = 78

3 0
3 years ago
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