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3 years ago

A rectangular picture 6cm by 8cm is enclosed by a frame 1/2cm wide . calculate the area of the frame.

Mathematics

2 answers:

Stels [109]3 years ago

6 0

Answer:

i have no clue wats so ever

aksik [14]3 years ago

5 0

Answer:

15cm square

Step-by-step explanation:

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Reflect C over the y axis

4vir4ik [10]

Answer:

C' (- 3, 2 )

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

C (3, 2 ) → C' (- 3, 2 )

4 0

3 years ago

Which of the following statements is true according to the measurements in the diagram?

e-lub [12.9K]

Let's look at the corresponding ratios:

$\frac{AB}{ED}=\frac{24}{30}=\frac{4}{5}\\\frac{BC}{DC}=\frac{16}{20}=\frac{4}{5}\\\frac{AC}{EC}=\frac{21}{28}=\frac{3}{4}\\$

And we see that the three aren't equal.

Hence, $\Delta ABC$ and $\Delta EDC$ are not similar.

8 0

3 years ago

Read 2 more answers

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

Find the length of the segment AB

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

Find the cosine of the angle BAD

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

Find the length of the segment AC

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

Find the length of the segment DC

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

Find the length of the segment BC

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

the answer is

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

Please help, I have no idea what you are spossed to do.

Likurg_2 [28]

Me neither. I used to know, good luck!

8 0

4 years ago

PLZZ HELP IM IN THE NEED OF HELP LOOK IN THE PICTURE answer all 3 plzzzzz

Verdich [7]

17) 146 min.
18) 5 hrs and 31 min
19) -1/6

4 0

3 years ago

Read 2 more answers

A rectangular picture 6cm by 8cm is enclosed by a frame 1/2cm wide . calculate the area of the frame.​

A rectangular picture 6cm by 8cm is enclosed by a frame 1/2cm wide . calculate the area of the frame.