For this case we have that by definition of trigonometric relations of rectangular triangles, that the sine of an angle is given by the opposite leg to the angle on the hypotenuse of the triangle. So:
Where h is the hypotenuse.
We cleared h:
We rationalize:
ANswer:
Option A
Answer: For the system given, there is no solution.
The slopes are the same for both equations, so the lines are parallel. With no intersection, there is no solution.
It may be easier to graph the system if you change the equations to slope intercept form y = mx + b
That locates the y-intercept, <em><u>b</u></em> and you can use the slope, <em><u>m</u></em> to plot additional points to draw the lines.
The attachment shows the graph of this system of equations.
Step-by-step explanation: Isolate y on the left
<u>First equation:</u>
4x + 6y = -12 Subtract 4x from both sides
6y = -4x -12 Divide both sides by 6
y = -4x/6 -12/6 Simplify
y = -2x/3 - 2 The y-intercept is -2, <u>the slope is -2/3</u>
<u>Second equation:</u>
2x + 3y = 6 Subtract 2x from both sides
3y = –2x + 6 . Divide both sides by 3
y = –2x/3 + 6/3 Simplify
y = –2x/3 +2 The y-intercept is -2, <u>the slope is -2/3 </u>
At this point we see that the slopes are the same, so the lines are parallel.
Answer:
Step-by-step explanation:
Product of of 3 and b is 3b
At least means greater than or equal too.